Advertisements
Advertisements
Question
A labourer is engaged for 20 days on the condition that he will receive Rs 60 for each day, he works and he will be fined Rs 5 for each day, he is absent. If he receives Rs 745 in all, for how many days he remained absent?
Solution
Let the number of days for which the labourer is absent be x .
Therefore, the number of days for which he is present will be (20 - x) .
∴ Earnings = Rs . 60(20 - x)
Fine = Rs . 5x
According to the question,
60(20 - x) - 5x = 745
or 1200 - 60x - 5x = 745
or 65x = 1200 - 745
or\[ x = \frac{455}{65} = 7\]
Thus, the labourer was absent for 7 days.
APPEARS IN
RELATED QUESTIONS
The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.
Four-fifth of a number is more than three-fourth of the number by 4. Find the number.
Divide 184 into two parts such that one-third of one part may exceed one-seventh of another part by 8.
A sum of Rs 800 is in the form of denominations of Rs 10 and Rs 20. If the total number of notes be 50, find the number of notes of each type.
Sunita is twice as old as Ashima. If six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times Ashima's age. How old were they two years ago?
I am currently 5 times as old as my son. In 6 years time I will be three times as old as he will be then. What are our ages now?
At a party, colas, squash and fruit juice were offered to guests. A fourth of the guests drank colas, a third drank squash, two fifths drank fruit juice and just three did not drink any thing. How many guests were in all?
Ravish has three boxes whose total weight is \[60\frac{1}{2}\] kg. Box B weighs \[3\frac{1}{2}\] kg more than box A and box C weighs \[5\frac{1}{3}\] kg more than box B. Find the weight of box A.
The sum of the ages of Anup and his father is 100. When Anup is as old as his father now, he will be five times as old as his son Anuj is now. Anuj will be eight years older than Anup is now, when Anup is as old as his father. What are their ages now?
Solve the following:
`(x + 1)/4 = (x - 2)/3`