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A manufacturer of TV sets produces 600 units in the third year and 700 units in the 7th year. Assuming that the production increases uniformly by a fixed number every year - Mathematics

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Question

A manufacturer of TV sets produces 600 units in the third year and 700 units in the 7th year. Assuming that the production increases uniformly by a fixed number every year, find:

  1. the production in the first year.
  2. the production in the 10th year.
  3. the total production in 7 years.
Sum

Solution

Since the production increases uniformly by a fixed number every year, the sequence formed by the production in different years in an A.P.

Let the production in the first year = a

Common difference = number of units by which the production increases  every year = d

We have, 

t3 = 600

`\implies` a + 2d = 600  ...(1)

t7 = 700

`\implies` a + 6d = 700   ...(2)

Subtracting (1) from (2), we get 

4d = 100

`\implies` d = 25

`\implies` a + 2 × 25 = 600

`\implies` a = 550

i. The production in the first year = 550 Tv sets

ii. The production in the 10th year = t10

= 550 + 9 × 25

= 775 Tv sets

iii. The total production in 7 years = S7

= `7/2[2 xx 550 + 6 xx 25]`

= `7/2 [1100 + 150]`

= `7/2 xx 1250`

= 4375 Tv sets

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Chapter 10: Arithmetic Progression - Exercise 10 (E) [Page 147]

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Selina Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
Exercise 10 (E) | Q 4 | Page 147
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