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Question
A manufacturer of TV sets produces 600 units in the third year and 700 units in the 7th year. Assuming that the production increases uniformly by a fixed number every year, find:
- the production in the first year.
- the production in the 10th year.
- the total production in 7 years.
Solution
Since the production increases uniformly by a fixed number every year, the sequence formed by the production in different years in an A.P.
Let the production in the first year = a
Common difference = number of units by which the production increases every year = d
We have,
t3 = 600
`\implies` a + 2d = 600 ...(1)
t7 = 700
`\implies` a + 6d = 700 ...(2)
Subtracting (1) from (2), we get
4d = 100
`\implies` d = 25
`\implies` a + 2 × 25 = 600
`\implies` a = 550
i. The production in the first year = 550 Tv sets
ii. The production in the 10th year = t10
= 550 + 9 × 25
= 775 Tv sets
iii. The total production in 7 years = S7
= `7/2[2 xx 550 + 6 xx 25]`
= `7/2 [1100 + 150]`
= `7/2 xx 1250`
= 4375 Tv sets
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