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Question
A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.
Solution
We have to find the distance travelled and final velocity of the body. We have the following information given,
Initial velocity, (u) = 5 m/s
Acceleration, (a) = 0.2 m/s2
Time taken, (t) = 10 s
So, we can find the final velocity using the relation,
v = u + at
So, final velocity,
v = 5 + (0.2)(10)
= 7 m/s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled by the motorcycle ,
`(s) = 5(10) + 1/2(0.2)(10)^2`
= (50 + 10) m
= 60 m
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