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Question
A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?
Solution
`e=-M(dI)/dt`
`e=-1.5xx(20-0)/0.5`
=−60 V
So, the flux linked with the other coil is given by
∆ϕ=e×∆t=−60×0.5=−30 Wb
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