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Question
A pair of nut crackers is 12 cm long. An effort of 10 gf is required to crack a nut which is passed at a point 3 cm from the finger. Calculate the load Fig.
Solution
Let L be the load.
Given, load arm = 3 cm
effort arm = 12 cm
Effort, E = 10 gf
Now, M.A = `"effort arm"/"load arm" = 12/3` = 4
Also MA = `"L"/"E"`
4 = `"L"/10`
or, L = 40 gf
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