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Question
A potential difference V is applied across a conductor of length l and cross-sectional area A. Briefly explain how the current density J in the conductor will be affected if
- the potential difference V is doubled.
- the conductor was gradually stretched to reduce its cross-sectional area to `A/2` and then the same potential difference V is applied across it.
Derivation
Short Note
Solution
- If potential difference 'V' is applied across a conductor of length 'l' and area of cross-section 'A' having the number of free electrons per unit volume n.
Then, the charge in the conductor,
q = neAl
and I = `q/t`
I = neAυd and υd = `(eE)/m xx tau`
where τ is the relaxation time and 'm' is the mass of the electron.
Therefore, the current per unit area i.e., current density,
J = `I/A`
J = neυd
J = `n e xx (eE)/m xx tau`
J = `(n e^2tau)/m xx (V/l)`
Hence, with an increase in potential different V, J increases. - J does not change when the area decreases because, according to relation (i), J is not reliant on A.
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