Advertisements
Advertisements
Question
A proton has spin and magnetic moment just like an electron. Why then its effect is neglected in magnetism of materials?
Solution
Spinning of a proton is negligible as compared to that of electron spin because its mass is very larger than the mass of an electron.
The comparison between the spinning of a proton and an electron can be done by comparing their magnetic dipole moment which can be given by
As we know that magnetic moment of a charged particle of charge e and mass m is Me = `(eh)/(4πme)` and Mp = `(eh)/(4πm p)`
As charge on proton and electron are equal in magnitude so
`M oo 1/m` or `M_e/M_p = m_p/m_e`
As the mass of proton is 1836 times as of electron, so magnetic moment of proton
`M_p = M_e/m_p m_e = (M_e * m_e)/(1836 m_e)`, `M_p = 1/1836` of `M_e`
So magnetic moment of proton is `1/1836` times of electron, so can be neglected.
APPEARS IN
RELATED QUESTIONS
An iron needle is attracted to the ends of a bar magnet but not to the middle region of the magnet. Is the material making up the ends of a bare magnet different from that of the middle region?
Choose the correct option.
Inside a bar magnet, the magnetic field lines
Answer the following question in detail.
Two bar magnets are placed on a horizontal surface. Draw magnetic lines around them. Mark the position of any neutral points (points where there is no resultant magnetic field) on your diagram.
A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 × 10–2 J. What is the magnitude of magnetic moment of the magnet?
In which case of comparing solenoid and bar magnet there is no exact similarity?
Magnetic moment for solenoid and corresponding bar magnet is ______.
At a certain 100 p of reduces 0.0/57 m carrier a current of 2 amp. The magnetic field at the centre of the coop is [`mu_0 = 4pi xx 10^-7` wb/amp – m]
A particle having charge 100 times that of an electron is revolving in a circular path by radius 0.8 with one rotation per second. The magnetic field produced at the centre is
Verify the Ampere’s law for magnetic field of a point dipole of dipole moment m = m`hatk`. Take C as the closed curve running clockwise along (i) the z-axis from z = a > 0 to z = R; (ii) along the quarter circle of radius R and centre at the origin, in the first quadrant of x-z plane; (iii) along the x-axis from x = R to x = a, and (iv) along the quarter circle of radius a and centre at the origin in the first quadrant of x-z plane.