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A Right Angled Triangle Whose Sides Are 3 Cm, 4 Cm and 5 Cm is Revolved About the Sides Containing the Right Angle in Two Days. Find the Difference in Volumes of the Two Cones So Formed. Also, Find Their Curved Surfaces. - Mathematics

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Question

A right angled triangle whose sides are 3 cm, 4 cm and 5 cm is revolved about the sides containing the right angle in two days. Find the difference in columes of the two cones so formed. Also, find their curved surfaces.

Solution

(i) Given that radius of cone(r1) = 4cm

Height of cone (h1) 3cm

Slant height of cone(l1) = 5cm

Volume of cone`(V_1)=1/3pir_1^2h_1`

`=1/3pi(4)^2(3)=16picm^3`

(ii) Given radius of second cone (r2) = 3cm

Height of cone(h2) = 4cm

Slant height of cone (l2) = 5cm

Volume of cone`(V_2)=1/3r_2^2h_2`

`=1/3pi(3)^2(4)=12picm^3`

Difference in volumes of two cones(V) = V1 - V2

V = 16π - 12π

V = 4πcm3

Curved surface area of first cone(S1) = πr1l1

S1 =π( 4)(5) = 20πcm2

Curved surface area of second cone(S2) = πr2l2

S2 = π(3)(5) = 15πcm2

S1 = 20πcmS2 = 15πcm2

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Chapter 14: Surface Areas and Volumes - Exercise 14.1 [Page 31]

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RD Sharma Mathematics [English] Class 10
Chapter 14 Surface Areas and Volumes
Exercise 14.1 | Q 59 | Page 31

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