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Question
A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH4NO3 → N2O + 2H2O
What mass of ammonium nitrate should be heated to produce 8.96L of steam?
Solution
Molecular mass of NH4NO3 = 80
44.8L of steam is liberated by = 80g of NH4NO3
8.96L of steam will be liberated by = 80 x 8.96 / 44.8 = 16L
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