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Question
A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH4NO3 → N2O + 2H2O
What volume of dinitrogen oxide is produced at the same time as 8.96 L of steam?
Solution
NH4NO3 → N2O + 2H2O
From the equation:
1 mole of NH4NO3 yields 2 mole of H2O.
So, 44.8L of steam = 22.4L of N2O at STP.
8.96L of Steam = 22.4 x 8.96/44.8 = 4.48L of N2O at STP.
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