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Question
A spherical metal ball of radius 15 cm carries a charge of 2μC. Calculate the electric field at a distance of 20 cm from the center of the sphere.
Solution
Given:
R = 15 cm= 15 x 10−2 m
q = 2 µC = 2 x 10−6 C
To find:
Eat distance (r), where
r = 20 cm = 20 × 10−2 m = 2 × 10−1 m
Formula:
`E = 1/(4 pi epsilon_0) q/r^2`
We know, 1/(4 pi epsilon_0) = 9 xx 10^9
`therefore E = 9 xx 10^9 xx (2 xx 10^-6)/((2 xx 10^-1)^2`
= `9 xx 10^9 xx (2 xx 10^-6)/(4 xx 10^-2)`
= 4.5 × 105 N/C
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