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Question
A student calculates experimentally the value of density of iron as 7.4 gcm−3. If the actual density of iron is 7.6 gcm−3, calculate the percentage error in the experiment.
Solution
Experimental value of density of iron = ρ1 = 7.4 gcm−3
Actual value of density of iron = ρ2 = 7.6 gcm−3
Absolute error = ρ2 − ρ1 = 7.6 − 7.4 = 0.2 gcm3
Percentage error = `"Absolute error"/"Actual value"xx100`
= `0.2/7.6xx100`
= `100/38`
= 2.63%
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