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Question
A toy company manufactures two types of dolls, A and B. Market tests and available resources have indicated that the combined production level should not exceed 1200 dolls per week and the demand for dolls of type B is at most half of that for dolls of type A. Further, the production level of dolls of type A can exceed three times the production of dolls of other type by at most 600 units. If the company makes profit of ₹ 12 and ₹ 16 per doll respectively on dolls A and B, how many of each should be produced weekly in order to maximise the profit?
Solution
Let \[x\] units of doll A and \[y\] units of doll B are manufactured to obtain the maximum profit.
The mathematical formulation of the above problem is as follows:
Maximize \[Z = 12x + 16y\]
Subject to
\[x + y \leq 1200\]
\[y \leq \frac{x}{2}\]
\[x - 3y \leq 600\]
\[x, y \geq 0\]
The shaded region represents the set of feasible solutions.
The coordinates of the corner points of the feasible region are O(0,0), A(800,400), B(1050,150) and C(600,0).
\[= 12\left( 0 \right) + 16\left( 0 \right) = 0\]
The value of Z at A(800,400) \[= 12\left( 800 \right) + 16\left( 400 \right) = 16000\] (Maximum)
The value of Z at B(1050,150) \[= 12\left( 1050 \right) + 16\left( 150 \right) = 15000\]
The value of Z at C(600,0)
\[= 12\left( 600 \right) + 16\left( 0 \right) = 7200\]
Therefore, 800 units of doll A and 400 units of doll B should be produced weekly to get the maximum profit of Rs 16000.
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