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Question
A wooden bookshelf has external dimensions as follows: Height = 110 cm, Depth = 25 cm, Breadth = 85 cm in following figure. The thickness of the plank is 5 cm everywhere. The external faces are to be polished and the inner faces are to be painted. If the rate of polishing is 20 paise per cm2 and the rate of painting is 10 paise per cm2. Find the total expenses required for polishing and painting the surface of the bookshelf.
Solution
External length of book shelf = 85cm = l
Breadth= 25cm
Height = 110cm.
External surface area of shelf while leaving front face of shelf
`=lh+2(lb+bh)`
`=[85xx110+21(85xx25+25xx110)]"cm"^2`
`= 19100"cm"^2`
Area of front face = `(85xx110-75xx100+2(75xx5))"cm"^2`
`=1850+ 750"cm"^2`
`=2600"cm"^2`
Area to be polished = `19100+2600"cm"^2`
`=21700"cm"^2`
Cost of polishing `1"cm"^2`"area" = "Rs". 0.20
Cost of polishing `21700"cm"^2 `are `= "Rs".[21700xx0.20]`
`= "Rs". 4340`
Now, length (l), breath (b), height (h) of each row of book shelf is 75cm, 20cm and 30cm
`((110-20)/3)` respectively.
Area to be painted in row `= 2(l+h)b+lh`
`=[2(75+30)xx20+75xx30]"cm"^2`
`=(4200+2250)"cm"^2`
`=6450"cm"^2`
Area to be painted in 3 rows `=(3xx6450)"cm"^2`
`=19350"cm"^2`
`"Cost of painting" 1"cm"^2 area = Rs. 0.10`
`"Cost of painting 19350 area" = Rs.(19350 xx 0 .10) - "Rs".1935`
Total expense required for polishing and painting the surface of the bookshelf
= Rs.(4340 +1935) = Rs. 6275.
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