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Question
Add: 2a + b + 3c and `"a" + 1/3"b" + 2/5"c"`
Sum
Solution
`2"a" + "b"+ 3"c" + ("a" + 1/3"b" + 2/5"c")`
= `2"a" + "b" + 3"c" + "a" + 1/3"b" + 2/5"c"`
= `(2 + 1)"a" + (1 + 1/3)"b" + (3 + 2/5)"c"`
= `3"a" + (3/3 + 1/3)"b" + (15/5 + 2/5)"c"`
= `3"a" + 4/3"b" + 17/5"c"`
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