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Question
After a meeting, every participant shakes hands with every other participants. If the number of handshakes is 66, find the number of participants in the meeting.
Solution
Let there be n participants present in the meeting.
A handshake occurs between 2 persons.
Then, the number of ways of selecting any 2 persons from them = nC2
Now, in all 66 handshakes were exchanged.
∴ nC2 = 66
∴ `("n"!)/(("n" - 2)!2!)` = 66
∴ `("n" xx ("n" - 1) xx ("n" - 2)!)/(("n" - 2)!)` = 66 × 2
∴ n(n – 1) = 132
∴ n(n – 1) = 12 × 11
Comparing on both sides, we get
∴ n = 12
∴ The number of participants in the meeting = 12
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