Advertisements
Advertisements
Question
Aluminium crystallizes in a cubic close packed structure. Its metallic radius is 125 pm. calculate the edge length of the unit cell.
Solution
Cubic close packing is based on face centered cubic unit cell.
For fcc structure (r) = `("a"sqrt2)/4`
Given, Radius (r) = 125 pm
Edge length of unit cell (a) = ?
∵ r = `("a"sqrt2)/4`
∴ a = `(4"r")/sqrt2`
= `(4 xx 125)/1.414`
a = 353.6 pm
APPEARS IN
RELATED QUESTIONS
The number of unit cells in 8 gm of an element X (atomic mass 40) which crystallizes in bcc pattern is (NA is the Avogadro number)
CsCl has bcc arrangement, its unit cell edge length is 400 pm, it's inter atomic distance is
The vacant space in bcc lattice unit cell is ____________.
The radius of an atom is 300 pm, if it crystallizes in a face centered cubic lattice, the length of the edge of the unit cell is ____________.
The fraction of total volume occupied by the atoms in a simple cubic is
What is the coordination number of atoms in a bcc structure?
An element has bcc structure with a cell edge of 288 pm. the density of the element is 7.2 g cm−3. how many atoms are present in 208 g of the element.
KF crystallizes in fcc structure like sodium chloride. calculate the distance between K+ and F− in KF.
(Given: density of KF is 2.48 g cm−3)
Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube and Y is at the centre of the cube. What is the formula of the compound?
Sodium metal crystallizes in bcc structure with the edge length of the unit cell 4.3 × 10−8 cm. calculate the radius of a sodium atom.
