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Question
An alkyl bromide (A) reacts with sodium in ether to form 4, 5 – diethyloctane, the compound (A) is
Options
CH3(CH2)3Br
CH3(CH2)5Br
CH3(CH2)3 CH(Br)CH3
\[\begin{array}{cc}\ce{CH3 - (CH2)2 - CH(Br) - CH2}\\\phantom{.........................}|\\
\phantom{............................}\ce{CH3}
\end{array}\]
Solution
\[\begin{array}{cc}\ce{CH3 - (CH2)2 - CH(Br) - CH2}\\\phantom{.........................}|\\
\phantom{............................}\ce{CH3}
\end{array}\]
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