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Question
An element has a bee structure with unit cell edge length of 288 pm. How many unit cells and number of atoms are present in 200 g of the element?
Solution
For bcc unit cell, n = 2
Using formula (i),
Number of atoms in 200 g of element,
= `(200 g xx 2)/(14.44 g cm^-3 xx (2.88 xx 10^-8 cm)^3`
= 9.61 × 1024
Using formula (ii),
∴ Number of atoms in 200 g element is 9.61 × 1024
∵ Number of unit cells in 200 g element is 4.80 × 1024
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