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Question
An object is thrown with an initial speed of 5 m s-1 with an angle of projection of 30°. What is the height and range reached by the particle?
Solution
Given,
Initial speed (u) = 5 ms-1
The angle of projection θ = 30°
Solution:
Max height reached (Hmax) = `(u^2 sin^2theta)/(2g) = (25 xx (1/2)^2)/(2 xx 9.8) = 0.318` m
Range (R) = `(u^2sin2theta)/g = (25 xx sin 60^circ)/9.8` = 2.21 m
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