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Question
An object of 4 cm height is placed at 6 cm in front of a concave mirror of radius of curvature 24 cm. Find the position, height, magnification and nature of the image.
Solution
h = 4 cm
u = - 6 cm
R = - 24 cm
f = `"R"/2 = (- 24)/2` = - 12 cm
Find out: v = ?, I = ?, m = ?
Mirror formula,
1) `1/"f" = 1/"v" + 1/"u"`
`(-1)/12 = 1/"v" - 1/6`
`1/"v" = - 1/12 + 1/6`
`1/"v" = (- 1 + 2)/12 = 1/12`
v = 12 cm
2) `("I" ("h'"))/"h" = (- "v")/"u"`
I(h') = (- "v")/"u" (h)
`= (- 12)/(- 6)`
h' = 8 cm
3) m = `"I"/"O" = ("h"')/"h" = 8/4 = 2`
m = 2
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