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Question
An object is placed at a distance of 6 cm from a convex mirror of focal length 12 cm. Find the position and nature of the image.
Solution
Distance of the object (u) = -6cm
Focal length of the convex mirror (f) = 12 cm
We have to find the position of the image (v) and the nature of the image.
Using the mirror formula, we get:
⇒`1/f=1/v+1/u`
⇒`1/12=1/v+1/-6`
⇒`1/12=1/v-1/6`
⇒`1/12+1/6=1/v`
⇒`1/12+2/12=1/v`
⇒`1/v=3/12`
⇒`1/v=1/4`
v=4 cm
Thus, the distance of the image (v) is 4 cm behind the mirror.
Now, using the magnification formula, we get:
`m=(-v)/u`
`m=(-4)/-6=2/3`
m=0.6
Thus, the image is virtual, erect and small.
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