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Question
An unbiased cubic die is thrown .Find the probability of getting (i) an odd number,
Solution
When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6. So,
total number of possible outcomes =6
The event is getting an odd number and the odd numbers are 1,3,5. So, the number of favourable outcomes to the event getting an even number = 3
Therefore , P(getting an odd number) = `"Favourable outcomes"/"Total number of outcomes"` = `3/6` = `1/2`
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