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Question
An unbiased cubic die is thrown .Find the probability of getting
(ii) a number greater than 2
Solution
When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6. So,
total number of possible outcomes =6
The event is getting a number greater than 2 and numbers greater than 2 are 3,4,5,6. So, the number of favourable outcomes to the event getting a number greater than 2 =4
Therefore , P(getting a number greater than 2) = `"Favourable outcomes"/"Total number of outcomes"` = `4/6` = `2/3`
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