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Question
An unbiased cubic die is thrown .Find the probability of getting
(iii) a number divisible by 2
Solution
When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6. So,
total number of possible outcomes =6
The event is getting a number divisible by 2 and numbers divisible by 2 are 2,4,6. So, the number of favourable outcomes to the event getting a number divisible by 2 = 3
Therefore , P(getting a number divisible by 2) = `"Favourable outcomes "/"Total number of outcomes "` = `3/6` = `1/2`
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