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Question
A and B are friends. Ignoring the leap year, find the probability that both friends will have different birthdays?
Solution
Out of the two friends, A's birthday can be any day of the year. Now, B's birthday can also be any day of 365 days in the year.
We assume that these 365 outcomes are equally likely.
If A's birthday from B's, the number of favourable outcomes for his birthday is 365 – 1 = 364
So, P(A's birthday is different from B's birthday) = `364/365`
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