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Question
A perfect cubic die is thrown .Find the probability that
(ii) a perfect square comes up.
Solution
When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6
So, total number of possible outcomes =6
The event is getting a perfect square and the perfect squares are 1 and 4 .
So ,the number of favourable outcomes to the event getting a perfect square =2
Therefore, P(getting a perfect square)= `"Favourable outcomes"/"Total number of outcomes"` = `2/6` = `1/3`
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