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Question
A perfect cubic die is thrown .Find the probability that
(i) an even number comes up
Solution
When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6
So, total number of possible outcomes =6
(i)The event is getting an even number and the even numbers are 2,4,6.
So , the number of favourable outcomes to the event getting an even number =3
Therefore, P(getting an even number)= `"Favourable outcomes"/"Total number of outcomes"` = `3/6` = `1/2`
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