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Question
A die is thrown once. The probability of getting a prime number is
Solution
`1/2`
Explanation:
In a single throw of a die, the possible outcomes are:
1, 2, 3, 4, 5, 6
Total number of possible outcomes = 6
Let E be the event of getting a prime number.
Then, the favourable outcomes are 2, 3 and 5.
Number of favourable outcomes = 3
∴ Probability of getting a prime number = P (E) = `("Number of favourable outcomes")/("Number of all possible outcomes")=3/6 = 1/2`
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