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Question
An urn contains 12 red balls, 15 yellow balls and 18 blue balls. A ball is choosen at random, then to find the probability of choosing a blue and red coloured balls, fill in the boxes.
Total number of balls = 12 + `square` + `square` = `square`
(1) Let E be the event that the choosen ball is blue.
Number of blue balls = `square`
Thus,
P(E) = `"Number of blue balls"/"Total number of balls"`
= `square/square`
(2) Let F be the event that the choosen ball is red.
Number of red balls = `square`
Thus,
P(F) = `square/"Total number of balls"`
= `square/square`
Solution
Total number of balls = 12 + 15 + 18 = 45
(1) Let E be the event that the choosen ball is blue.
Number of blue balls = 18
Thus,
P(E) = `"Number of blue balls"/"Total number of balls"`
= `bb18/bb45`
(2) Let F be the event that the choosen ball is red.
Number of red balls = 12
Thus,
P(F) = `bb("Number of red balls")/"Total number of balls"`
= `bb12/bb45`
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