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Question
In the adjoining figure, the arrow rests on any number, after the rotation of the disc. The probability that it will rest on any of the numbers on the disc is equal. Let A be any random event. To find the probability of A, fill in the boxes.
(1) S = `square`
(2) n(S) = `square`
(3) Let A be the event that arrow points at the number which is perfect cube.
A = `square`
∴ n(A) = `square`
(4) ∴ P(A) = `(n(A))/(n(S)) = square/square = square`
Solution
(1) S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}
(2) n(S) = 12
(3) A = {1, 8}
∴ n(A) = 2
(4) ∴ P(A) = `(n(A))/(n(S)) = bb2/bb12 = bb(1/6)`
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