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Question
Arrange surds in descending order:
`root(2)root(3)(5), root(3)root(4)(7), sqrt(sqrt(3)`
Solution
`root(2)root(3)(5) = root(6)(5), root(3)(root(4)(7)) = root(12)(7), sqrt(sqrt(3)) = root(4)(3)`
L.C.M of 6, 12 and 4 is 12
`root(2)root(3)(5) = root(6)(5) = root(12)(5^2) = root(12)(25)`
`root(3)(root(4)(7)) = root(12)(7) = root(12)(7)`
`sqrt(sqrt(3)) = root(4)(3) = root(12)(3^3) = root(12)(27)`
`root(12)(27) > root(12)(25) > root(12)(7)`
`sqrt(sqrt(3)) > root(2)root(3)(5) > root(3)(root(4)(7)`
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