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Question
If `sqrt(80) = "k"sqrt(5)`, then k =
Options
2
4
8
16
Solution
4
Explanation;
Hint:
`sqrt(80) = "k"sqrt(5)`
`sqrt(16 xx 5) = "k"sqrt(5)`
`4sqrt(5) = "k"sqrt(5)`
∴ k = 4
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