Advertisements
Advertisements
Question
Assertion: The highest oxidation state of osmium is +8.
Reason: Osmium is a 5d-block element.
Options
Both assertion and reason are true, and reason is the correct explanation of the assertion.
Both assertion and reason are true but reason is not the correct explanation of assertion.
Assertion is not true but reason is true.
Both assertion and reason are false.
Solution
Both assertion and reason are true but reason is not the correct explanation of assertion.
Explanation:
Osmium has the capacity to expands its octet by utilising all the electrons from its 6s and 5d orbitals this results it attaining an oxidation state of +8.
APPEARS IN
RELATED QUESTIONS
ln which pair highest oxidation states of transition metals are found:
The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co
Answer the following: Which element is a strong oxidising agent in +3 oxidation state and why?
To what extent do the electronic configurations decide the stability of oxidation states in the first series of the transition elements? Illustrate your answer with examples.
Use Hund’s rule to derive the electronic configuration of Ce3+ ion and calculate its magnetic moment on the basis of ‘spin-only’ formula.
Write the factors which are related to the colour of transition metal ions.
Out of \[\ce{Cu2Cl2}\] and \[\ce{CuCl2}\], which is more stable and why?
The second and third rows of transition elements resemble each other much more than they resemble the first row. Explain why?
Match the solutions given in Column I and the colours given in Column II.
| Column I (Aqueous solution of salt) |
Column II (Colour) |
| (i) \[\ce{FeSO2.7H2O}\] | (a) Green |
| (ii) \[\ce{NiCl2.4H2O}\] | (b) Light pink |
| (iii) \[\ce{MnCl2.4H2O}\] | (c) Blue |
| (iv) \[\ce{CoC12,6H2O}\] | (d) Pale green |
| (v) \[\ce{Cu2 Cl2}\] | (e) Pink |
| (f) Colourless |
It has been observed that first ionization energy of 5 d series of transition elements are higher than that of 3d and 4d series, explain why?
A complex in which dsp2 hybridisation takes place is
