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Question
Bond dissociation enthalpy of E–H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent?
| Compound | \[\ce{NH3}\] | \[\ce{PH3}\] | \[\ce{AsH3}\] | \[\ce{SbH3}\] |
| Δdiss (E – H)/kJ mol–1 | 389 | 322 | 297 | 255 |
Options
\[\ce{NH3}\]
\[\ce{PH3}\]
\[\ce{AsH3}\]
\[\ce{SbH3}\]
Solution
\[\ce{SbH3}\]
Explanation:
\[\ce{SbH3}\] will act as strongest reducing agent due to minimum bond enthalpy.
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