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Question
Calcium carbonate react with dilute hydrochloric acid as given below:
\[\ce{CaCO3 + 2HCl -> CaCl2 + H2O + CO2}\]
What is the mass of 5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100)
Solution
1 mole of \[\ce{CaCO3}\] = 100 g
5 moles of \[\ce{CaCO3 -> 5 × 100}\] = 500 g
Hence, the mass of 5 moles of \[\ce{CaCO3}\] will be 500 g
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