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Question
Calcium carbonate react with dilute hydrochloric acid as given below:
\[\ce{CaCO3 + 2HCl -> CaCl2 + H2O + CO2}\]
How many moles of \[\ce{HCl}\] will react with 5 moles of calcium carbonate?
Solution
2 moles of HCl are used for 1 mole of \[\ce{CaCO3}\]
i.e., \[\ce{CaCO3}\] \[\ce{HCl}\]
\[\ce{1mole -> 2 mole}\]
\[\ce{5 mole -> 5 × 2 = 10 moles}\]
Hence 10 moles of HCl will react with 5 moles of calcium carbonate.
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Calcium carbonate react with dilute hydrochloric acid as given below:
\[\ce{CaCO3 + 2HCl -> CaCl2 + H2O + CO2}\]
What is the mass of 5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100)
