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Question
Write the name of the following compound and deduce its molecular mass.
NaHCO3
Solution
NaHCO3 - Sodium bicarbonate
| Molecule | Constituent elements | Atomic mass u | Number of atoms in the molecule | Atomic mass × number of atoms | Mass of the Constituents u |
| NaHCO3 | Na | 23 | 1 | 23 × 1 | 23 |
| H | 1 | 1 | 1 × 1 | 1 | |
| C | 12 | 1 | 12 × 1 | 12 | |
| O | 16 | 3 | 16 × 3 | 48 |
The molecular mass of NaHCO3 = Sum of Constituent atomic masses
(Molecular mass of NaHCO3) = (Atomic mass of Na) × 1 + (Atomic mass of H) × 1 + (Atomic mass of C) × 1 + (Atomic mass of O) × 3
= (23 × 1) + (1 × 1) + (12 × 1) + (16 × 3)
= 23 + 1 + 12 + 48
= 84 u
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