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Question
Calculate the degree of hydrolysis of 0.2 (M) sodium acetate solution.
(Hydrolysis constant of sodium acetate = 5.6 × 10-10 and ionic product of H2O = 10-14 at 25°C).
Solution
Degree of hydrolysis h = `sqrt((K_h)/c)`
Given, Kh = 5.6 × 10-10
c = 0.2 M
Hence, `h = sqrt((5.6xx10^-10)/0.2) = 5.29 xx 10^-5`
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