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Question
Calculate the number of unpaired electrons in Ti3+, Mn2+ and calculate the spin only magnetic moment.
Solution
Ti3+:
Ti (Z = 22)
Electronic configuration [Ar] 3d2 4s2
Ti3+ – Electronic configuration [Ar] 3d1
So, the number of unpaired electrons in Ti3+ is equal to 1.
Spin only magnetic moment of Ti3+ = `sqrt(1 (1 + 2)) = sqrt3` = 1.73 µB
Mn2+:
Mn (Z = 25)
Electronic configuration [Ar] 3d5 4s2
Mn2+ – Electronic configuration [Ar] 3d5
Mn2+ has 5 unpaired electrons.
Spin only magnetic moment of Mn2+ = `sqrt(5 (5 + 2)) = sqrt35` = 5.91 µB
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