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Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1 A and 2 A. - Physics

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Question

Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1 A and 2 A. The gases may be considered under identical conditions of temperature, pressure and volume.

Short Note

Solution

Mean free path of a molecule is given by `l = 1/(sqrt(2)d^2n)`

Where n = number of molecules/volume

d = diameter of the molecule

Now, we can write `l ∝ 1/d^2`

Given, `d_1 = 1Å, d_2 = 2Å`

As `l_1 ∝ 1/d_1^2` and `l_2 ∝ 1/d_2^2`

⇒ So, `l_1/l_2 = (d_2/d_1)^2 = (2/1)^2 = 4/1`

Hence, `l_1 : l_2` = 4 : 1

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Chapter 13: Kinetic Theory - Exercises [Page 94]

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NCERT Exemplar Physics [English] Class 11
Chapter 13 Kinetic Theory
Exercises | Q 13.19 | Page 94

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