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Calculate the ratio of two specific heats of polyatomic gas molecules. - Physics

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Question

Calculate the ratio of two specific heats of polyatomic gas molecules.  

Numerical

Solution

  1. Gases that have molecules containing more than two atoms are termed polyatomic gases.
  2. Each molecule of the polyatomic gas has 3 translational degrees of freedom. Only linear molecules have 2 degrees of freedom for rotation. All other polyatomic molecules have 3 degrees of freedom for rotation.
  3. The number of degrees of freedom (f) for the vibrational motion of a polyatomic molecule depends on the geometric structure of the molecule, i.e., the arrangement of atoms in a molecule.
  4. Each such degree of freedom contributes average energy `2 xx 1/2`kBT from kinetic energy and potential energy terms.
  5. Therefore for 1 mole of a polyatomic gas, the internal energy is E = `3/2 N_Ak_BT + 3/2 N_Ak_BT + f × 2/2 N_Ak_BT`
    = (3 + f) NAkB
  6. Molar-specificific heats at constant volume and constant pressure are given as 
    Cv = (3 + f) R and Cp = (4 + f) R
    ∴ `gamma = C_p/C_v = (4 + f)/(3 + f)`
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Chapter 3: Kinetic Theory of gases and Radiation - Short Answer II

APPEARS IN

SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 3 Kinetic Theory of gases and Radiation
Short Answer II | Q 3

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