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Question
Choose the correct alternative:
If A and B are any two events, then the probability that exactly one of them occur is
Options
`"P"("A" ∪ bar"B") + P(bar"A" ∪ "B")`
`"P"("A" ∩ bar"B") + P(bar"A" ∩ "B")
P(A) + P(B) – P(A ∩ B)
P(A) + P(B) + 2P(A ∩ B)
Solution
`"P"("A" ∩ bar"B") + P(bar"A" ∩ "B")
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