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Question
Choose the most correct option.
Pressure cooker reduces cooking time for food because _______.
Options
boiling point of water involved in cooking is increased
heat is more evenly distributed in the cooking space
the higher pressure inside the cooker crushes the food material
cooking involves chemical changes helped by a rise temperature
Solution
Pressure cooker reduces cooking time for food because boiling point of water involved in cooking is increased.
Explanation:
The boiling point of a substance is the temperature at which the vapour pressure of a liquid equals the pressure surrounding the liquid and the liquid changes to vapour.
Normally, when we cook food, the temperature inside rises until the water begins to boil. The temperature of the system will not rise at boiling point because heat is utilised to boil the water.
However, when we cook food in a pressure cooker, the temperature at which water boils rises as the pressure within the pressure cooker rises.
As the surrounding pressure rises, so does the boiling point temperature. As a result, instead of boiling the water, the heat will raise the temperature of the system. Food cooks faster at higher temperatures because cooking reactions speed up.
RELATED QUESTIONS
Answer the following.
How vapour pressure lowering is related to a rise in the boiling point of solution?
The following solution/solvent has maximum vapour pressure _______.
According to Raoult’s law, relative lowering of vapour pressure of solution containing dissolved nonvolatile solute _______.
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Which of the following is NOT a colligative property?
The vapour pressure of solvent decreases by 1 O mm Hg, if mole fraction of non-volatile solute is 0.2. Calculate vapour pressure of solvent.
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Relative lowering of vapour pressure of a solution of non-volatile solute depend only on ____________.
Which of the following is CORRECT for a solution containing non-volatile solute in it?
In an experiment, 1 g of a non-volatile solute was dissolved in 100 g of acetone (molar mass = 58 g mol−1) at 298 K. The vapour pressure of the solution was found to be 192.5 mm Hg. The molecular weight of the solute is (vapour pressure of acetone = 195 mm Hg) ____________ g mol−1.
The vapour pressure of pure benzene (molar mass 78 g/mol) at a certain temperature is 640 mm Hg. A nonvolatile solute of mass 2.315 g is added to 40 g of benzene. The vapour pressure of the solution is 600 mm Hg. The molar mass of solute is ____________.
At a constant volume, a quantity of an ideal gas has a pressure of 700 mm Hg at 300 K. At what pressure, the temperature will be halved?
According to Raoult's law, relative lowering of vapour pressure for a solution containing a nonvolatile solute is equal to ____________.
Relative lowering in vapour pressure of a solution containing non-volatile solute is the ratio of ____________.
Which of the following is INCORRECT expression in terms of vapour pressure of pure solvent `("P"_1^0)` and that of solution (P)?
Which of the following changes will cause increase in vapour pressure of 1 molal aqueous KI solution at same temperature?
What will be the molar mass of solute if vapour pressure of pure benzene is 450 mm Hg when 1.5 g of non-volatile solute is added to 30 g of benzene?
(Vapour pressure of solution= 400 mm Hg, Atomic mass C = 12, H = 1)
12 g of a nonvolatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0.1. The molecular mass of the solute is ______.
The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent its vapour pressure drops to 0.6 atm. the mole fraction of B in the solution is ______.
Which of the following solutions will have the maximum lowering of vapour pressure at 300 K?
Calculate the mole fraction of solute, if the vapour pressure of pure benzene at a certain temperature is 640 mmHg and the vapour pressure of a solution of a solute in benzene is 600 mmHg.
