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Question
Complete the following calculations. Show working for complete credit :
Calculate the mass of calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur. [Atomic masses : S = 32, Ca = 40]
Solution
3.2g of S has number of atoms = 6.023 × 1023 x 3.2 /32
= 0.6023 × 1023
So, 0.6023 × 1023 atoms of Ca has mass
= 40 × 0.6023 ×1023/6.023 × 1023 = 4g
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