Advertisements
Advertisements
Question
Consider sunlight incident on a pinhole of width 103A. The image of the pinhole seen on a screen shall be ______.
- a sharp white ring.
- different from a geometrical image.
- a diffused central spot, white in colour.
- diffused coloured region around a sharp central white spot.
Options
a and c
a and d
b and d
b and c
Solution
b and d
Explanation:
Diffraction of Light can be observed only if the size of obstacle/aperture is less than the wavelength of light.
Given, width of pinhole = 103 Å = 1000 Å
We know that wavelength of sunlight ranges from 4000 Å to 8000 Å. Clearly, wavelength X < width of the slit.
Hence, light is diffracted from the hole. Due to diffraction from the slit, the image formed on the screen will be different from the geometrical image.
APPEARS IN
RELATED QUESTIONS
First diffraction minimum due to a single slit of width 1.0 × 10-5 cm is at 30°. Then wavelength of light used is ______.
What is diffraction?
Discuss the special cases on first minimum in Fraunhofer diffraction.
What is Fresnel’s distance? Obtain the equation for Fresnel’s distance.
Discuss diffraction at single slit and obtain the condition for nth minimum.
Discuss the diffraction at a grating and obtain the condition for the mth maximum.
Discuss the experiment to determine the wavelength of different colours using diffraction grating.
Obtain the equation for resolving power of optical instrument
What is the difference between resolution and magnification?
Consider sunlight incident on a slit of width 104 A. The image seen through the slit shall ______.