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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Discuss the diffraction at a grating and obtain the condition for the mth maximum. - Physics

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Question

Discuss the diffraction at a grating and obtain the condition for the mth maximum.

Long Answer

Solution

  1. Grating has multiple slits with equal widths of size comparable to the wavelength of diffracting light.
  2. Grating is a plane sheet of transparent material on which opaque rulings are made with a fine diamond pointer.
  3. The rulings act as obstacles having a definite width b and the transparent space between the rulings act as slit of width a.
  4. The combined width of a ruling and a slit is called grating element (e = a + b). Points on successive slits separated by a distance equal to the grating element are called corresponding points.Diffraction grating experiment
  5. Let a plane wavefront of monochromatic light with wave length λ be incident normally on the grating.
  6. As the slits size is comparable to that of wavelength, the incident light diffracts at the grating.
  7. A diffraction pattern is obtained on the screen when the diffracted waves are focused on a screen using a convex lens.
  8. The path difference δ between the diffracted waves from one pair of corresponding points is,
    δ = (a + b) sin θ
    This path difference is the same for any pair of corresponding points. The point P will be bright, when
    δ = mλ where m = 0,1,2,3
    Combining the above two equations, we get,
    (a + b) sin θ = mλ
    Here, m is called an order of diffraction.
    1. Condition for zero order maximum, m = 0
      For (a + b) sinθ = 0, the position, θ = 0. sin θ = 0 and m = 0. This is called zero order diffraction or central maximum.
    2. Condition for first-order maximum, m = 1
      If (a + b) sin θ1 = λ, the diffracted light meet at an angle θ1 to the incident direction and the first-order maximum is obtained.
    3. Condition for second-order maximum, m = 2
      Similarly, (a + b) sin θ2 = 2λ forms the second-order maximum at the angular position θ2.
      Condition for higher-order maximum
      On either side of central maxima, different higher orders of diffraction maxima are formed at different angular positions.
      If we take,
      N = `1/("a + b")`
      `1/"N"` sin θ = mλ (or) sin θ = Nmλ
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Diffraction of Light
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Chapter 7: Wave Optics - Evaluation [Page 104]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 7 Wave Optics
Evaluation | Q 8. | Page 104
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