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Question
Consider the following molecular formulae of carbon compounds:
(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8
- Which one of these compounds belongs to homologous series of alcohols?
- Identify the compound having triple bond between carbon-carbon atoms.
- Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
- Write the general formula of the series to which the compound C4H8 belongs.
Solution
- Methanol (CH3OH) belongs to homologous series of alcohols.
- C3H4 has triple bond between carbon atoms.
- Methanoic acid (HCOOH)
- General formula of C4H8 is CnH2n.
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