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Construct a Parallelogram Pqrs in Which Pq = 6.4cm, Qr = 4cm and the Distance Between Pq and Sr is 3cm. - Mathematics

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Question

Construct a parallelogram PQRS in which PQ = 6.4cm, QR = 4cm and the distance between PQ and SR is 3cm.

Sum

Solution


Steps of Construction:
1) Draw PQ = 6.4cm.
2) At Q, draw QX perpendicular to PQ.
3) From QX, cut QT = 3cm = distance between PQ and SR.
4) Through T, draw a perpendicular to QX to get ZY parallel to PQ.
5) With P as centre and radius = QR = 4cm, draw an arc which cuts ZY at S.
6) With Q as centre and radius = 4cm, draw an arc which cuts ZY at R.
7) ABCD is the required parallelogram.

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Construction of Parallelograms
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Chapter 20: Constructions of Quadrilaterals - Exercise 20.1

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Frank Mathematics [English] Class 9 ICSE
Chapter 20 Constructions of Quadrilaterals
Exercise 20.1 | Q 4
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