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Question
Construct a parallelogram ABCD, when:
AB = 4.5 cm, ∠B = 120° and the distance between AB and DC = 3.0 cm.
Solution
Steps:
1. Draw AB = 4.5 cm.
2. At B, draw BP ⊥ AB.
3. From BP cut BE = 3 cm.
4. Through E draw a perpendicular to BP to get QR parallel to AB.
5. With B as a center draw an arc that cuts QR at C.
6. With A as a center draw an arc that cuts QR at D.
7. Now join AD and BC.
ABCD is the required parallelogram.
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